Unit Test 1: Number System
Class 10 Mathematics (Standard)
General Instructions:
- The question paper consists of 12 questions divided into 5 sections: A, B, C, D, and E.
- Section A: 5 questions (1-5) of 1 mark each.
- Section B: 3 questions (6-8) of 2 marks each.
- Section C: 2 questions (9-10) of 3 marks each.
- Section D: 1 Long Answer question (11) of 4 marks.
- Section E: 1 Case Study based question (12) of 4 marks.
- Use of calculators is not permitted.
Reason (R): A composite number has factors other than 1 and itself.
A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English, and Mathematics are 60, 84, and 108 respectively.
Based on the above information, answer the following questions:
(i) Find the prime factorization of 60, 84, and 108. (1 Mark)
(ii) In each room, the same number of participants are to be seated and all of them being in the same subject. Find the maximum number of participants that can be accommodated in each room. (2 Marks)
(iii) What is the minimum number of rooms required during the event? (1 Mark)
0 / 5 (MCQ)
(Includes your self-graded marks below)
Solution Key
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LCM × HCF = Product of numbers. LCM = 1800 / 12 = 150.
144 = 12² = (2² × 3)² = 2⁴ × 3². Exponent of 2 is 4.
√16=4, 3+√9=6, √2.25=1.5 are all rational. √5 is irrational.
Product of non-zero rational and irrational is irrational.
5×7×11 + 11 = 11(35+1) = 11×36. It has factors, so it is composite. Reason is correct definition.
26 = 2×13, 91 = 7×13. HCF = 13. LCM = 2×7×13 = 182.
6n = (2×3)n = 2n × 3n. Since the prime factorization does not contain the pair (2, 5), it cannot end with the digit 0.
7×11×13 + 13 = 13(7×11 + 1) = 13(78). Since it has factors other than 1 and itself, it is composite.
Assume √5 = a/b (coprime). a² = 5b² ⇒ 5 divides a. Let a=5c, then 25c²=5b² ⇒ b²=5c² ⇒ 5 divides b. Contradiction. Hence irrational.
They meet at LCM(18, 12). 18=2×3², 12=2²×3. LCM = 2²×3² = 36 minutes.
First prove √3 is irrational (standard proof). Then assume 5 + 2√3 = r (rational). √3 = (r-5)/2. LHS is irrational, RHS is rational. Contradiction.
(i) 60=2²×3×5, 84=2²×3×7, 108=2²×3³. (ii) HCF=12 participants/room. (iii) Total rooms = (60+84+108)/12 = 21.
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